Use the square command under the sample tools menu of Custom Tools and
construct two squares S (ABCD) and S' (EFGH) |
Use the straightedge tool and lay off a segment MP. |
Use the perpendicular command under the construct
menu and construct a perpendicular at M. |
Use the circle by center + radius command under the construct menu and
construct a circle with center at M and radius congruent to segment
AD. Label the intersection of MP and this circle N. |
Use the circle by center + radius command under the
construct menu and construct a circle with center at N and radius
congruent to EH. Label the intersection of the perpendicular and
this circle O. |
Use the segment command under the construct menu and construct a segment
MO. |
Use the straightedge tool and lay off a segment LQ. |
Use the perpendicular command under the construct
menu and construct a perpendicular at L. |
Use the circle by center + radius command under the construct menu and
construct a circle with center at L and radius congruent to segment
MO. Label the intersection of LQ and this circle I, the
intersection of the perpendicular at L and this circle K. |
Use the circle by center + radius command and construct a circle with
center at K and radius congruent to segment MO, and another circle with
center at I and radius congruent to MO. Label the intersection of
these two circles J. |
Quadrilateral S" (IJKL) is the required square. |
You may choose to construct the interiors of all three squares and then
calculate the areas to confirm the sketch. |
| Proof: |
(MN)^2 + (MO)^2 = (NO)^2 (The square of the hypotenuse of a right
triangle is equal to the sum of the squares of the legs.) |
(MO)^2 = (NO)^2 - (MN)^2
(Subtraction) |
S" = S' -
S (Substitution) |
|
| Sketch: Drag points A or E and
see if the calculations hold. |
|