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| Given: Points A, B, C |
| Required: To construct a
circle containing given points A, B, C. |
| Procedure: |
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Use the segment command under the construct menu,
to construct segments AB, BC, and CA. You now have a triangle, ABC
with points A, B, and C as vertices. |
Construct the perpendicular bisectors of two sides of the
triangle. This can be accomplished by following the basic
perpendicular bisector construction; (help, midpoint) (help, )
or by using the
tools in Sketchpad which follows: |
Select segment AB. |
Use the midpoint command under the construct menu
to place a midpoint on AB. Label it D. |
Select the midpoint D and segment AB, use the perpendicular line command
under the construct menu and construct a perpendicular at D. |
Select segment BC and repeat the above steps, but
label the midpoint E. |
Label the point of intersection of the two perpendicular bisectors point F. |
Use the segment command under the construct menu and construct segment
FB. |
Use the circle by center + radius command under the
construct menu and construct a circle with center F and radius
congruent to segment FB. |
This is the required circle. |
| Proof: |
F the intersection of the
bisectors. |
Segment FB = FA = FC
(The
bisector of the sides of a triangle are concurrent in a point
equidistant from the vertices) |
A, B, and C all lie on the same circle. (definition of circle) |
|
| Sketch: Drag points A, B, or C
around on the sketch below. Does the circle still contain all 3 points? |
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